Integrand size = 28, antiderivative size = 86 \[ \int \sec ^2(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {3 a b^2 \text {arctanh}(\sin (c+d x))}{d}-\frac {3 a^2 b \cos (c+d x)}{d}+\frac {b^3 \cos (c+d x)}{d}+\frac {b^3 \sec (c+d x)}{d}+\frac {a^3 \sin (c+d x)}{d}-\frac {3 a b^2 \sin (c+d x)}{d} \]
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Time = 0.13 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3169, 2717, 2718, 2672, 327, 212, 2670, 14} \[ \int \sec ^2(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {a^3 \sin (c+d x)}{d}-\frac {3 a^2 b \cos (c+d x)}{d}+\frac {3 a b^2 \text {arctanh}(\sin (c+d x))}{d}-\frac {3 a b^2 \sin (c+d x)}{d}+\frac {b^3 \cos (c+d x)}{d}+\frac {b^3 \sec (c+d x)}{d} \]
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Rule 14
Rule 212
Rule 327
Rule 2670
Rule 2672
Rule 2717
Rule 2718
Rule 3169
Rubi steps \begin{align*} \text {integral}& = \int \left (a^3 \cos (c+d x)+3 a^2 b \sin (c+d x)+3 a b^2 \sin (c+d x) \tan (c+d x)+b^3 \sin (c+d x) \tan ^2(c+d x)\right ) \, dx \\ & = a^3 \int \cos (c+d x) \, dx+\left (3 a^2 b\right ) \int \sin (c+d x) \, dx+\left (3 a b^2\right ) \int \sin (c+d x) \tan (c+d x) \, dx+b^3 \int \sin (c+d x) \tan ^2(c+d x) \, dx \\ & = -\frac {3 a^2 b \cos (c+d x)}{d}+\frac {a^3 \sin (c+d x)}{d}+\frac {\left (3 a b^2\right ) \text {Subst}\left (\int \frac {x^2}{1-x^2} \, dx,x,\sin (c+d x)\right )}{d}-\frac {b^3 \text {Subst}\left (\int \frac {1-x^2}{x^2} \, dx,x,\cos (c+d x)\right )}{d} \\ & = -\frac {3 a^2 b \cos (c+d x)}{d}+\frac {a^3 \sin (c+d x)}{d}-\frac {3 a b^2 \sin (c+d x)}{d}+\frac {\left (3 a b^2\right ) \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\sin (c+d x)\right )}{d}-\frac {b^3 \text {Subst}\left (\int \left (-1+\frac {1}{x^2}\right ) \, dx,x,\cos (c+d x)\right )}{d} \\ & = \frac {3 a b^2 \text {arctanh}(\sin (c+d x))}{d}-\frac {3 a^2 b \cos (c+d x)}{d}+\frac {b^3 \cos (c+d x)}{d}+\frac {b^3 \sec (c+d x)}{d}+\frac {a^3 \sin (c+d x)}{d}-\frac {3 a b^2 \sin (c+d x)}{d} \\ \end{align*}
Time = 1.10 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.52 \[ \int \sec ^2(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {\sec (c+d x) \left (-3 a^2 b+3 b^3+\left (-3 a^2 b+b^3\right ) \cos (2 (c+d x))-6 a b^2 \cos (c+d x) \left (\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-\log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )\right )+a^3 \sin (2 (c+d x))-3 a b^2 \sin (2 (c+d x))\right )}{2 d} \]
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Time = 0.98 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.12
method | result | size |
derivativedivides | \(\frac {a^{3} \sin \left (d x +c \right )-3 \cos \left (d x +c \right ) a^{2} b +3 a \,b^{2} \left (-\sin \left (d x +c \right )+\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )\right )+b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{\cos \left (d x +c \right )}+\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )\right )}{d}\) | \(96\) |
default | \(\frac {a^{3} \sin \left (d x +c \right )-3 \cos \left (d x +c \right ) a^{2} b +3 a \,b^{2} \left (-\sin \left (d x +c \right )+\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )\right )+b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{\cos \left (d x +c \right )}+\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )\right )}{d}\) | \(96\) |
parts | \(\frac {a^{3} \sin \left (d x +c \right )}{d}+\frac {b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{\cos \left (d x +c \right )}+\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )\right )}{d}+\frac {3 a \,b^{2} \left (-\sin \left (d x +c \right )+\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )\right )}{d}-\frac {3 a^{2} b \cos \left (d x +c \right )}{d}\) | \(104\) |
parallelrisch | \(\frac {3 \left (-\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+1\right ) b^{2} a \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+3 b^{2} a \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}-1\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+2 \left (a^{3}-3 a \,b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}-6 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a^{2} b +2 \left (-a^{3}+3 a \,b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+6 a^{2} b -4 b^{3}}{d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}-1\right )}\) | \(159\) |
risch | \(-\frac {3 \,{\mathrm e}^{i \left (d x +c \right )} a^{2} b}{2 d}+\frac {{\mathrm e}^{i \left (d x +c \right )} b^{3}}{2 d}-\frac {i {\mathrm e}^{i \left (d x +c \right )} a^{3}}{2 d}+\frac {3 i {\mathrm e}^{i \left (d x +c \right )} a \,b^{2}}{2 d}-\frac {3 \,{\mathrm e}^{-i \left (d x +c \right )} a^{2} b}{2 d}+\frac {{\mathrm e}^{-i \left (d x +c \right )} b^{3}}{2 d}+\frac {i {\mathrm e}^{-i \left (d x +c \right )} a^{3}}{2 d}-\frac {3 i {\mathrm e}^{-i \left (d x +c \right )} a \,b^{2}}{2 d}+\frac {2 b^{3} {\mathrm e}^{i \left (d x +c \right )}}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}+\frac {3 a \,b^{2} \ln \left (i+{\mathrm e}^{i \left (d x +c \right )}\right )}{d}-\frac {3 a \,b^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{d}\) | \(220\) |
norman | \(\frac {\frac {6 a^{2} b -4 b^{3}}{d}-\frac {6 a^{2} b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{d}+\frac {2 \left (3 a^{2} b -4 b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{d}-\frac {2 a \left (a^{2}-3 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}-\frac {2 a \left (a^{2}-3 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{d}+\frac {2 a \left (a^{2}-3 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{d}+\frac {2 a \left (a^{2}-3 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{d}-\frac {2 b \left (3 a^{2}+2 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{d}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right ) \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{3}}-\frac {3 a \,b^{2} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d}+\frac {3 a \,b^{2} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d}\) | \(270\) |
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Time = 0.26 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.27 \[ \int \sec ^2(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {3 \, a b^{2} \cos \left (d x + c\right ) \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, a b^{2} \cos \left (d x + c\right ) \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, b^{3} - 2 \, {\left (3 \, a^{2} b - b^{3}\right )} \cos \left (d x + c\right )^{2} + 2 \, {\left (a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right ) \sin \left (d x + c\right )}{2 \, d \cos \left (d x + c\right )} \]
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\[ \int \sec ^2(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\int \left (a \cos {\left (c + d x \right )} + b \sin {\left (c + d x \right )}\right )^{3} \sec ^{2}{\left (c + d x \right )}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.98 \[ \int \sec ^2(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {2 \, b^{3} {\left (\frac {1}{\cos \left (d x + c\right )} + \cos \left (d x + c\right )\right )} + 3 \, a b^{2} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right ) - 2 \, \sin \left (d x + c\right )\right )} - 6 \, a^{2} b \cos \left (d x + c\right ) + 2 \, a^{3} \sin \left (d x + c\right )}{2 \, d} \]
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Time = 0.35 (sec) , antiderivative size = 150, normalized size of antiderivative = 1.74 \[ \int \sec ^2(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {3 \, a b^{2} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 3 \, a b^{2} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) + \frac {2 \, {\left (a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 3 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 3 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3 \, a^{2} b - 2 \, b^{3}\right )}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 1}}{d} \]
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Time = 22.86 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.35 \[ \int \sec ^2(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {6\,a\,b^2\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{d}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (6\,a\,b^2-2\,a^3\right )-6\,a^2\,b-\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (6\,a\,b^2-2\,a^3\right )+4\,b^3+6\,a^2\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-1\right )} \]
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